How many different types of gametes can an individual of the genotype rrPp produce?

How many different types of gametes can an individual of the genotype rrPp produce?

• A. 1
• B. 2
• C. 3
• D. 4

Answer: (B)

To determine the number of different types of gametes produced by an individual with the genotype rrPp, we need to focus on the alleles present. In this individual, there are two genes of interest: one gene has the alleles "r" (homozygous recessive) and the other gene has the alleles "P" (dominant) and "p" (recessive). The first gene, rr, can only contribute "r" to the gamete since both alleles are the same (homozygous). Therefore, it only provides one type of allele for this gene. The second gene, Pp, can contribute either "P" or "p" to the gamete. Because this gene has two different alleles, this allows for variation in the gametes produced. To find the total number of distinct gametes, we multiply the possibilities provided by each gene. The rr genotype contributes 1 type of gamete, and the Pp genotype contributes 2 types of gametes. When calculating the total combinations, we have: 1 type from rr (only "r") × 2 types from Pp ("P" or "p") = 1 × 2 = 2

To determine the number of different types of gametes produced by an individual with the genotype rrPp, we need to focus on the alleles present.

In this individual, there are two genes of interest: one gene has the alleles "r" (homozygous recessive) and the other gene has the alleles "P" (dominant) and "p" (recessive). The first gene, rr, can only contribute "r" to the gamete since both alleles are the same (homozygous). Therefore, it only provides one type of allele for this gene.

The second gene, Pp, can contribute either "P" or "p" to the gamete. Because this gene has two different alleles, this allows for variation in the gametes produced.

To find the total number of distinct gametes, we multiply the possibilities provided by each gene. The rr genotype contributes 1 type of gamete, and the Pp genotype contributes 2 types of gametes. When calculating the total combinations, we have:

1 type from rr (only "r") × 2 types from Pp ("P" or "p") = 1 × 2 = 2